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1.2 2. Draw the structures of the cis-trans isomers for each compound Label them cis and trans Ifno cis-trans isomers exist, write none_ 2 3 dimethyl-2-pentene b. 1...

Question

1.2 2. Draw the structures of the cis-trans isomers for each compound Label them cis and trans Ifno cis-trans isomers exist, write none_ 2 3 dimethyl-2-pentene b. 1,1-dimethyl-2-ethykyclopropane 1,2-dimethykyclohexane d.5 methyk-2-hexene 1,23-trimethykyclopropane

1.2 2. Draw the structures of the cis-trans isomers for each compound Label them cis and trans Ifno cis-trans isomers exist, write none_ 2 3 dimethyl-2-pentene b. 1,1-dimethyl-2-ethykyclopropane 1,2-dimethykyclohexane d.5 methyk-2-hexene 1,23-trimethykyclopropane



Answers

Which of the following compounds can exist as cis and trans isomers? Draw and label them. (a) 2 -butene; (b) 1,2 -dibromo-2-butene; (c) 2 -bromo-2-butene; (d) 1,2 -dichlorocyclopentane

So we need to draw. Assistant Trans estimators for is to sew for air. We have to Pantene. So this is the CIS. Um this will be the trans right here. Many to Pantene. The beach is on the same side. This on since its two Pantene. It's gonna be ch three here on. And this is the siege. Teoh 234 stage three year. And it's the opposite on the other side. Like so Probably three. Heck scene missus looks like Yes, but trans is flipped. Put it over here for space make so look good.

So we're determining which of these molecules of have did you mentor Vice Tourism. All right, so started with a were just given propane. Um, So if we drop european like that, we have to ask yourself, this is subject much Christmas. Um, uh, the answer in this case is no. And the reason is that both I can kind of imagine drawing. Just read a hydrogen off this way, hydrogen off this way, Since there is no kind of cis trans there since both those abs issuance with same, this does not have geometric ice. More ism. All right. Also shifting a little bit and going to be We have three vaccine. All right, so I'll draw my vaccine, then go to the three position. Now, this does have CIS trans ice tourism. Um, where the other molecule would kind of. Look, it's kind of like that. All right, So the first name, uh, right here is obviously just going to be e um three hack scene, and this one would be Z three vaccine. Okay, so moving on to part C down just a little bit. Ah, we're going to have dyke. Loro anything. So one, uh, so I have 11 dyke. Laura. So do a CEO and a C L May I feed itself? Okay, so this does not have ice. More ism. And the reason is both sides are the same, right? There's two. Chlorine is on that one side. There's to Hodgins on the other. Uh, so this obviously doesn't have CIS trans ice first. All right. And then moving on to part D. We have to chlor a propane. All right, eso since the propane isn't named your kind of assuming it's on there in the two chlor right here. All right, so this actually does have CIS trans ice terrorism and the reason I'm sorry. No, it doesn't, because again, I can imagine you're only to hundreds right here and right here. Eso. Since there is no other alcohol off of this, there's no real way to determine its sisters. Is Trans? Uh, so that's gonna be that

So we need to draw CIS and trans eyes and ears for two beauty, not a structure, sis. Trans for a to beauty. There are the double bond. Since their cysts, the HSE have to be on the same side and this has to be three c. This is carbon one, 23 on them for and then for Trans. It's gotta be the opposite. Each year, each year just a c ch three cis trans of to heck Seen the same thing here H is gonna be on the same side one carping two or three carbon and 45 in six. This beach too. Age three. So it's 45 six. Same thing here, So there's gotta be on another side opposite side since their trans You can condense it here by writing it like such. So that's for good. And, uh, this could be it's good this this could be rewritten like I did right here.

This is the answer to Chapter one problem number 47 from the Smith Organic Chemistry textbook. Ah, and this problem gives us three molecular formulas and asks us to draw all of the possible I simmers for each formula. Um, and we're also told how many possible I summers there are for each formula s o for a we have C three h seven c l and we're told that there are two possible I simmers. Um, and so they look like this. So in both instances, we're gonna have the three carbon chain. Ah, and we can have the chlorine on the first carbon, or we can have it on the central carbon. Ah, and and so remember, if we were to try to draw one with the chlorine on third carbon, that would be exactly the same as having it on the first carbon. Ah, and so we don't We don't consider that Ah, 1/3 ice summer, because it's exactly the same. So then for B r formula is C two h 40 um and so rather than using the letter notation, I'm going to draw the skeletal structures. Um, although actually, for this one I am going to leave it in in the letter notation. Um and so we have three possible i summers of C two h for Oh, so they're going to look like this, so we can have, uh, the O h here, Uh, or we can have, uh, carbon double bonded toe. Or we could have, um, what's known as an a pox side, which is a three member ID ring with an oxygen in it on. I guess I did say I would leave it with letter notation. Uh, so this is our third possibility. Okay. And then, lastly for see, the formula that were given is C three h, nine N, c three h nine and on, and we're told that there are four possibilities here. Um, so the 1st 1 would be just a straight chain 123 uh, in each too. Um, and so remember, each each corner and line intersection is a carbon, and we omit the Hydra jin's. So, really, there are three Hodgins here to here and to hear, but typically, we omit them when we're doing this skeletal drawings. So that's one possibility. Um, the next possibility would be, uh, putting the nitrogen at the middle carbon instead. So, uh, that's an except little structure. Um, we could also put the nitrogen in the chain. So, like this, Um, and we could also, uh, put the nitrogen with three methyl groups on it. So, like this, um and so those are the four possibilities there? Um and so remember this this 4th 1 is really this. I wouldn't want to confuse anyone if you're new to, uh, the line drawings. So the 4th 1 is really that the nitrogen in the centre were three method groups around it, but yes. So those were the four possibilities for C on. That's the answer to Chapter one. Problem number 47.


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