This is the answer to Chapter one problem number 47 from the Smith Organic Chemistry textbook. Ah, and this problem gives us three molecular formulas and asks us to draw all of the possible I simmers for each formula. Um, and we're also told how many possible I summers there are for each formula s o for a we have C three h seven c l and we're told that there are two possible I simmers. Um, and so they look like this. So in both instances, we're gonna have the three carbon chain. Ah, and we can have the chlorine on the first carbon, or we can have it on the central carbon. Ah, and and so remember, if we were to try to draw one with the chlorine on third carbon, that would be exactly the same as having it on the first carbon. Ah, and so we don't We don't consider that Ah, 1/3 ice summer, because it's exactly the same. So then for B r formula is C two h 40 um and so rather than using the letter notation, I'm going to draw the skeletal structures. Um, although actually, for this one I am going to leave it in in the letter notation. Um and so we have three possible i summers of C two h for Oh, so they're going to look like this, so we can have, uh, the O h here, Uh, or we can have, uh, carbon double bonded toe. Or we could have, um, what's known as an a pox side, which is a three member ID ring with an oxygen in it on. I guess I did say I would leave it with letter notation. Uh, so this is our third possibility. Okay. And then, lastly for see, the formula that were given is C three h, nine N, c three h nine and on, and we're told that there are four possibilities here. Um, so the 1st 1 would be just a straight chain 123 uh, in each too. Um, and so remember, each each corner and line intersection is a carbon, and we omit the Hydra jin's. So, really, there are three Hodgins here to here and to hear, but typically, we omit them when we're doing this skeletal drawings. So that's one possibility. Um, the next possibility would be, uh, putting the nitrogen at the middle carbon instead. So, uh, that's an except little structure. Um, we could also put the nitrogen in the chain. So, like this, Um, and we could also, uh, put the nitrogen with three methyl groups on it. So, like this, um and so those are the four possibilities there? Um and so remember this this 4th 1 is really this. I wouldn't want to confuse anyone if you're new to, uh, the line drawings. So the 4th 1 is really that the nitrogen in the centre were three method groups around it, but yes. So those were the four possibilities for C on. That's the answer to Chapter one. Problem number 47.