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18. A tennis ball has mass 0.0577 kg: For a typical player; the force exerted by the racket is 330 N for 0.008 sec. Calculate the Impulse on the ball from this stri...

Question

18. A tennis ball has mass 0.0577 kg: For a typical player; the force exerted by the racket is 330 N for 0.008 sec. Calculate the Impulse on the ball from this strike.Calculate the velocity ofthe ball immediately after the strike

18. A tennis ball has mass 0.0577 kg: For a typical player; the force exerted by the racket is 330 N for 0.008 sec. Calculate the Impulse on the ball from this strike. Calculate the velocity ofthe ball immediately after the strike



Answers

Just before it is struck by a racket, a tennis ball weighing 0.560 N has a velocity of $(20.0 m/s)\hat{\imath} - (4.0 m/s)\hat{\jmath}$. During the 3.00 ms that the racket and ball are in contact, the net force on the ball is constant and equal to $-(380 N)\hat{\imath} + (110 N)\hat{\jmath}$. What are the $x$- and $y$-components (a) of the impulse of the net force applied to the ball; (b) of the final velocity of the ball?

Welcome back to New Ron. My name is Kevin Chirac, so let's take a look here where we say it's not uncommon for a professional tennis player to exert an average force of 150 Newtons. We can write that in 150. Newtons of Force on a Ball for about 0.30 seconds will write that in its time 0.3 seconds. We do know that the mass the ball is going to be equal. Teoh 0.60 kilograms and we're being asked to figure out what the kinetic energy of the ball is as it leaves the racket. Now, if we look here, we do have force and time, and we know that forced times time is equal. Teoh M. Times V because forced times, times by impulse and M temps V is my momentum so I can plug in what I know here to get 150 times 0.3 equals the mass, which is 0.6 times the velocity and the velocity is what I'm trying to sell for, right? So let's go and solve that out. There's gonna be 150 times 1500.3 divided by a 0.6 gives me that the velocity is equal to 75 meters per second. Now, from trying to solve out for the kinetic energy That's just 1/2 times M, which I know is 0.6 times via squared, which is going to be 75 squared. We can plug all that in. That's going to 0.5 times 75 squared times 750.6 And that results in 169 Jewels of energy. Kinetic energy. All right, Hope you enjoyed this video. If you did, please take a moment and click that heart at the bottom of screen.

We have given just before it is struck by a racket. A tennis ball. Weight is given 0.560 newton. Okay, Has a velocity. Velocity is given in middle per 2nd 20. I kept minus for Jacob. This is the velocity which is given during the three milliseconds. Delta T is three into 10 to the power minus three seconds. An external force on the wall is constant and equal to f is equal to minus three D noodle in my cab and 110. Jacob, this is the force you just given. We have to find X and y component of the impulse and the final velocity. Right. So we know that impulse Jay is a call to f into Delta T. Right. So the n X component will be called to FX into Delta T now X component of forces 3 80 Newton in negative in two Delta history into 10 to the power minus three. So if we solve this, this will be equal to, uh this will be equal to minus 1.14 Newton second. Yeah, this is the X component of impulse now, similarly, we can find the Y component. This will be called to wife confident of forces. 110 in 23 and 2. 10 to the power minus three. So this will be called to 0.33 Newton second, so x component of impulses minus 1.14 Newton second. And why confident is 0.33 Newton second. Right now we have to find the velocity component also right. We know that momentum is equal to change in. So the impulse is a This is impulse impulse is a call to change in momentum. Right? Change in we do minus people. Right? So mhm feet will be equal to mass into velocity like this. So from here we can find we too. We too will be called to G by m plus we even Victor. So from here momentum We know this momentum is minus 1.14 I kept plus 0.33 Jacob, divided by mass Mass has given 0.0 zero point Now where it is given Mass is not given, So we will find the mass first. Mars will be called to W i G. So this will be called a 0.57 kg. Right. So the value of Mars we will put here 0.57 Plus we even vividness 20 icap's minus 40. Jacob. So we can solve this. We get this is equal to 0.5 I kept plus to 1.775 Jacob. So this is the ex confident. And this is the way confident the to access 0.5 Yeah. And we to buy years 1.775 Understood. Thank.

Hi. In a given problem, we have been given a force. Morse's Time car. My shown. Yeah. This is the force represented on the Y axis. And this is the time in seconds it doesn't turn on the X axis. The horse is in Newton and the good as well, given as approximately like this. So if you want to find out, the impulse in bubbles is given us Avia. Oh, force worse is time cut and approximately. We consider this ship as off a triangle so you can see the impulse. Yeah, with the area. Oh, she did triangle. No. The maximum force which we find here in this girl is approximately Do 150 new done. And the base off this triangle. If we count, it comes out to be a approximately 0.1 second. If we can't under blocs, the picked off on the blocks Clearly it comes out of the 0.1 2nd So 80 off shaded triangle is having an expression off half into base into heights. And this we are solving for the first part of the problem. So for base, it could become 0.1 2nd and for height between become 250 Newton. So then we saw this. The impulse finally comes out to be 1.5 new done into second. This is the answer for the first problem. First part of the problem? No. In the second part of the problem, we have to find the velocity of the ball after being struck. If its initial velocity was zero, so then we can say impose. We can take in purse as a change in momentum means final momentum minus initial momentum. The F minus B I and this momentum is given us mosque multiplied by velocity. So it becomes M times off me f minus m times off me I But initial velocity was zero. So the total impulse is equal toe m times off the F. So velocity achieved by this ball, the beginning as the ratio off impulse with the moss off the tennis ball and impulse we have found already in the first part of the problem, it was 1.25 new turn into second. The mask off the tennis ball here has been given a 0.60 kilogram. So finally this velocity achieved by the tennis ball here comes out to be 20 point it meter for second. This is the answer for the second part of the problem. Thank you.

Hello, everyone. This is problem one from Chapter five says you and a friend of playing tennis, eso party says, was the magnitude of the mo mentum of the 0.57 kilograms tennis ball when it travels at a speed of 30 meters per second. Okay, so, um, one of the main things we should remember about momentum is how it's defined in terms of a mass and velocity. So remember that momentum and ah, right as a vector just to remind you that it is electrical. Andi, although in this problem will mainly just be concerned with the magnitude physical M times the vector V. Okay, so it says parties is was a magnitude and it gives us the mass and the speed not bossy. But we know that of course, this means that the magnitude of the momentum which will just call p but here for clarity sake all right, the magnitude of the vector here for a second says p equals M V is generally what you'll see. Just keep in mind that's a vector quantity. So, of course, if we want the momentum of a 0.57 kilogram tennis ball traveling at 30 meters per second. I was just going to be equal to the product of these two. Just 1.71 kilogram meters per second approximately so that's party part B. Ah, it says at what speed muster 0.32 kilogram tennis racket move to have the same magnitude. Momentum is the bowl. Okay, so now we want the same mo mentum. So again, using peoples on the But now we want to find what V is the speed so V should just bp over m and we know the mo mentum we want is this 1.71 kilogram meters per second and on the bottom, it tells us that Iraq is 0.32 kilograms. Just put that there and we get approximately 5.34 meters per second in part C. It asks if you run toward the ball speed of five minutes per second in the balls flying directly at you. A speed of 30 meters per second was the magnitude of the total momentum of the system, which is you and the ball and then assuming massive 60 kilograms. All right, so here we actually do have to be a little bit concerned about the signs of the sign of the moment. Um, because, um, you're going one way and the ball is going the other, which means that if we find the magnitude of, ah, the person's momentum and then the men to the ball's movement and we actually have to subtract them, okay, because they're going in in different directions. Um, so this is, um this is the momenta MB of you, the person. So since you're 60 kilograms and running at five minutes per second, you get 5 to 60 kilogram meters per second mo mentum and the ball 30 times 300.57 referencing the mass that was given earlier kilogram meters per second. And so Ah, um, doing this taking this difference get approximately 298.3 kilogram meters per second. So we see that the vast majority of this of this momentous actually coming for the person and very little. There's actually very little a magnitude of momentum coming from the ball


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