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Acetate In 175. JV mL of ethanol (pure percent U solution a density of 0.809 made Ji 34.1 8 of solid sodium...

Question

Acetate In 175. JV mL of ethanol (pure percent U solution a density of 0.809 made Ji 34.1 8 of solid sodium

acetate In 175. JV mL of ethanol (pure percent U solution a density of 0.809 made Ji 34.1 8 of solid sodium



Answers

A solution of sodium acetate $\left(\mathrm{NaCH}_{3} \mathrm{COO}\right)$ has a pH of 9.70. What is the molarity of the solution?

In this problem. We're told that 45 grams of camper is dissolved in 425 milliliters of ethanol were asked to find the morality mole fraction and weight percent of camp for in the solution, we can start by finding our moles of camp for so we'll take our Mueller Mass and divide so we can't flatter grams and end up with moles. So within our solution, we have 0.296 multi camper. And now we can take our volume of ethanol that we have in our solution and use the density that we were given in the problem statement to find or mass of ethanol that we have present so we can multiply by that density to get it in two grams rather than milliliters. So we have 333 0.6 to 5 grams of ethanol present in our solution. We confined animal ality by taking the moles of camp for that we calculated above and dividing by the mass of ethanol in kilograms. So the number that we calculated for grams of ethanol is not in the correct units. So we can do a quick unit conversion here where we divide by 1000 grams in the denominator and Armel ality is equal 2.886 Mullah to find her weight percent, we can take the mass of camp for that. We were given in the problem statement and then we're going to divide by the total mass of our solution. So we're going to add the massive camp. For that we dissolved to the massive ethanol that we found by using or density. And then we're going to multiply this number by 100 since we wanted any percentage. So when we do that math, we find that the weight percent of camper and the solution is 11.9%. And our last step is to find the mole fraction so we can take the massive ethanol that we have calculated above and divide by the molar mass of ethanol to go from grams to moles. So we find that we have 7.24 moles of ethanol presence. Now, to find the mole fraction, we will take our moles of camper, and as we did with our weight percent, we're going to add up all of the moles that we have in our system. So we're going to add our most of camp for to the moles of ethanol that we calculated above. And when we do this division, we find that the mole fraction of camper and the solution is equal to 0.393

We dissolve 45 grams of camp for which is C 10 h 16 0 Ah We can calculate some information We have 425 milliliters of s and all See to H five h that is equal to you Point 4 to 5 grand kilograms on 425 grams which we will use here in a few minutes First thing we can calculate is morality which is moles over kilograms. So I need to calculate the number of moles I've got a camp for. So I take 45 grams prodded by the mouse off camp for which is 152 grams and I get 3.3 moles on I divide up by the mass in kilograms of my solvent which is 0.4 to 5 kilograms. And then I simply divide and I get 7.95 Millau The mole fraction is the number of moles of our saw You'd so 3.3 moles again divided by the moons of our Salyut plus the moles of our solvent On the moles are solvent is 9.24 molds I calculated that the same way I did four camp for, um, I got the mass of ethanol, which is 46 grams. So I take the 425 grams, divided by 46 grams classical toe, one more. When I divide that, I get the 9.2 formals. When I add and divide this, I get point 27 for my mole for action and then the mouse percent similar to the mall for action. I need the masses, Love. Are Salyut insolvent? So we've got 45 grams. We're Salyut, divided by 45 grams plus 425 grounds and that equals 0.96 times 100 and that gives us 9.6%.

In this problem, we have to calculate mask off it and all with the given density and volume. As for the question given for density, it is density is equal to mass. Divided by volume. This can be rewritten as mass is equal to density multiplied by volume. Now we have two values off density, which is 0.798 gram per ml and volume which is given a 17.4 Emily. Substituting these values into the creation it gives us mass which comes out toe 13.885 gram are tickling toe 13.89 grand.

All right. So we have kind of an interesting question here, and it has to do a little bit with Malala tea and also kind of with being able to convert between moles and grams using more mass. And so the question is asking us you what mass of a solution Ingrams would we need to result with 0.1 50 moles of sodium acid Tate if the solution is 0.500 morale. And so first, what's gonna make sure we understand what we're talking about with Malala t So the morality formula, the way it's defined, his morality is equal to the moles of the saw yout per the kilograms of the solvent. Now the angle in this entire problem is they've asked for the mass in grams of a solution. And so what we have to be careful about is knowing that the solution consists of two parts. So not only do we need the grands of the solvent, but we also need to include the grams of the Sol Ute and by combining those two pieces will be able to get the mass of the overall solution. So let's go ahead and fill in the parts that we know to them allow the formula. So they tell us a solution is 0.50 allow. And they also tell us that we know the moles of saw you to be 0.1 50. So what that opens up the door for us to do is to solve for the kilograms of salt. And so we'll do this by taking 0.1 50 dividing by 0.500 just kind of the alto over there to solve for X. And so what that gives us is 0.3, Ooo kilograms of are solvent. Now we know that they would like the mass and grand. So we need one final step. And that's to multiply by 1000 to convert from kilograms two grands so as Graham's that'll equal 300 grams So pencil that in as our grands of solvent. Now we need to go ahead and find our grams of salt. You'd are. Sawyer is called sodium acetate, and they tell us that we have 0.1 50 moles of it, and they give us the chemical formula for sodium acid. Tate. So ch three CEO too, and a so just like we would Any other time we could go for moles to grams using the molar mass from the periodic table so we would add up to carbons plus three hydrogen Tze was to Oxygen's plus one sodium and that gets us 82.0 for grands per one mole. When we multiply and dew 0.1 50 times 82.4 of the numerator we get 12.3 grams of our song You'd so know what we'll do to get the overall mass and the solution is combined Those together Did you sic figs? When we're adding, we're going to round off to the ones place So instead of 312.3, our final massive solution will be 312 grams and there we go.


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