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# 9u(x,t) d2u(x,t) dx2 dt2For 0 < x <1,0 <t <1 With initial boundary conditions:du(x,t) u(x,0) = 0, =5 sin(Tx), att=0 u(0,t) = 0, u(1,t) = 0 Note that the...

## Question

###### 9u(x,t) d2u(x,t) dx2 dt2For 0 < x <1,0 <t <1 With initial boundary conditions:du(x,t) u(x,0) = 0, =5 sin(Tx), att=0 u(0,t) = 0, u(1,t) = 0 Note that the true analytical solution is u(x,t) = 2.5/n sin(nx) sin (2nt)

9u(x,t) d2u(x,t) dx2 dt2 For 0 < x <1,0 <t <1 With initial boundary conditions: du(x,t) u(x,0) = 0, =5 sin(Tx), att=0 u(0,t) = 0, u(1,t) = 0 Note that the true analytical solution is u(x,t) = 2.5/n sin(nx) sin (2nt)

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