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$\mathrm{FcCl}_{\text {j }}$ solurion addcd ro $\mathrm{K}_{i}\left[\mathrm{Fc}(\mathrm{CN})_{6}\right]$ givcs (a) while with KSCN gives (b). (a) and (b) respecrively arc (a) $\mathrm{Fe}_{1}\left[\mathrm{Fe}(\mathrm{CN})_{\mathrm{G}}\right]_{3}, \mathrm{~K}_{3}\left[\mathrm{Fe}(\mathrm{SCN})_{6}\right]$ (b) $\mathrm{\Gammae}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}, \mathrm{~K}_{3}\left[\mathrm{Fe}(\mathrm{CNS})_{6}\right]$ (c) $\mathrm{Fc}_{3}\left[\mathrm{Fc}(\mathrm{CN})_{i}\right]_{2}, \mathrm{Fc}(\mathrm{CNS})_{3}$ (d) $\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}, \mathrm{KFe}(\mathrm{CNS})_{3}$

Hi everyone. So in this question they asked the electronic compilation of four elements are given as and uh one is managed to reassure people. The second managed to two years to do before 30s managed to do is to to be 3420s. When I should we ask you to pay six years 23 people? Which of the following enrichment gives the character order in terms of increasing electronic equity of lemons. So option she is correct. Oh son. Yeah. See is correct. Mhm correct. Alder off. Okay. Increasing electronic entity of the lemon teas increasing. Okay. Mhm. Electronica activity. Mm. Mhm. Yeah. Of the element ease. Mm As follows. Yeah. One X two creation To be 6 3 ash too three p 1 we can say at live India smaller than Okay. One is to to rest. Oh yeah to be three that is nitrogen which is smaller than nice to us to be for decades oxygen. Mhm Yeah, it is smaller than 1" to 3 years to to be for you that is floating chlorine. Is the lament having a guest electronic. It'd in the periodic table Florrie is the Lemon Read I. Yeste 11 12 negativity in the periodic table and erotic devil. Thanks loved

So any problem 1 75 of chapter six compounds of P block elements to so in this question, majesty following. Uh so uh 40 xenon cetera fluoride, which is xia for So this is the structure of the non tetra fluoride as seen on having the eight valence electron. And uh out of these four are the bond peers and involved and who are the lone lone pairs? So these are the long pair of electrons. So that makes uh it's a scare planner. So it has four bond pair and too long beard. So that makes, its hybridization is basically sp three due to. Okay, so uh shape is this carefully? Okay, so next is the non hexafluoride. X. EF six. So this is the structure in which six bond pair and one lone pair. So this is distorted Octa federal. And makes its hybridization sp three D three. So it's hybridization is sp three D three and its shape is distorted of capital. So the next is ex ceo three. So this is the pyramidal shape and then we have XC offer and this is the battleship. So therefore the correct match becomes for a. That is much with the R. For be that much with the B. Foresee, that is S. And for the that is your

Okay. So we're going to want to as our overall reaction, Platinum two plus Put Plus four chlorides gives us our complex ion because we're given the K. Of formation, Right? So that is one Times 10 to the 16th. We're going to be able to use that to find E0. So then the two equations that make that up the first one I need to that were given. I need to reverse. Okay, so platinum plus four chlorides give us our complex ion. That's why I need to reverse it. I need the complex ion on the right plus two electrons. So I reversed it so I'll change the sign of the voltage given. So negative .73V now. And our other half reaction is the platinum being reduced ion being reduced to platinum. And that's the voltage that we're trying to find. So if I can find this voltage, I can use it to then find that one. So let's go ahead and use the relationship between E zero and K. Alright, so .0257 over N. Is the Ellen of K. So E zero is .0257. And you can see above that our end is too Times The Ellen of one times 10 of the 16. So this is going to give us a voltage your point 473V. Mhm. So this so we know that negative .73V plus exports has to equal .473 Bolts. So just write that out as a kind of a sentence. 7 3 plus x Is .473. So our voltage is going to be 1.20V for this missing equation here.

In this problem, we can say that yellow solution yellow solution is your pain. Yellow solution Is your pain due to oxidation due to oxidation of see A three plus to c r 04 two minus iron on acidification, C r 04 to minus irons, changes to change to orange color, changed to orange colored CR 207 to minus items. So according to the option, option A is correct.


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