Implies the presence of a dominant B yields straight hair, whereas the presence of homeless I guess recess it for bees yields bitch hair. However, if the fly has a capital I or a dominant I'll Leo, that fly will be hairless regardless of what Gino type it has for hair shape. And so that also tells us that two little eyes we know that has no FINA type. So that means that a fly that has straight hair must have two little eyes and one big B. And so the question, for a part, says, What are the Gina types of FINA types of parents as one and F two from a breeding event from a straight here fly with a fly that was hairless but is no to have Vint Gino type, which the scientists would have to tell us. We could not infer that from the information provided it had to be told to us, it's a straight hair means that this fly is recessive for I because little eyes have no fino type and straight hair is big big. We have to assume that these flies were true breeding and hairless needs that that fly is homicide is dominant for hairless So big I, big guy and bent to Little Bee's and those who are parents. And so in the F one that crosses pretty easy. That fly for those flies are headers, I guess, for both traits and their hairless with the hidden strata Leo and a hidden bench the wheels. And so if we do an F one by F one Cross, we can expect that the offspring in the F two we'll have a 9 to 33 to one ratio. Because you have to jeans, I assume that they independently is sort. Otherwise, the question would have to tell us. And so we know that the feeding typical ratio in the F two is 9331 So that means nine flies will have a dominant olio for hairless and a dominant olio for straight and said they will be hairless. Three flies will have a dominant A Leo for hairless and ah, homeless, I guess process of state for bent that they will be hairless because of the presence of that ought. Assemble dominant Khalil. Three flies will have two little eyes and have a big B and something, and so that Fly will have straight here. And then the last individual will have been tear and be the double recessive. And so, uh, just used the information you have to fill in what? No and then work your way through this problem. But we can take that approach to be, he says. What are the parents Gina types If the offspring are four hairless, three straight and one bit. And so if we start out, let's write down everything we know and so hairless has to be big eyes, something, something, something. Because we don't know if they have the strata. Leo's works. The bins on wheels, straits and bends are easier because they have to have ah, homeless August recess it for I because they have hair and straight is gonna be big Be something and benches too little beast because we know that Vince is the double recesses. So let's start out writing the parents based on the information we have. And so we know that each parents must have one little I and a little be otherwise. This Gina type for the bent individual is not possible, and so we can easily right the parents genotype like that with something little eyes, something little. Being cross food is safe now. The second little tidbit that's over here that we can use to our advantage is the presence of a dominant eye in these hairless individuals and the presence of a dominant be in the straight hair individuals. And so that tells us that only one parent at this point we're not moving forward. One parent contains an IA Leo that's dominant and a B khalil that started it. And so what we could do is just stick those a wheels in the first parents Gina type, and we have that we're finished. The second piece of information that's here is if we look at the Gina typical ratio. It was a female typical ratio. We have a ratio of hairless, which is four t to haired, which is also for that's 1 to 1. The way to get a wonder one ratio is to breed a headers. I go with the homeless August recess of individual, and so because we could do a quick cross here and we can see big I little I two little eyes. They guide little I bigeye little like those two will be hairless. And then the two little eyes here would have hair. And so that's what we have. We have a wonder one ratio of hairless two straight that tells us that one parent is headers, I guess for I and the other parent is homeless, I just recesses for I using the same strategy, but a different characteristic. We can determine the be part of this second parent off the flies that have hair. We have three of them with straight hair and one of them with men's hair. So the only way to get it 3 to 1 ratio is to breathe to headers. I gets together, and so if we do a quick cross here, what we would see is that three of the individuals would have straight hair, as indicated by the big B. So 123 and only one individual will have been Well, that's what we have in our ratio in the this offspring batch. And so that means that this parent is think Big B and the second pier must also be, I think, the little B. And so my advice from problems like this take it for what it's worth it's right down as much information as you can and then work your way through each gene with the knowledge you have because you have so much college you have 93 321 at punitive pick ratio, where you could look for 1 to 1 or 3 to 1, and then you could tackle these seemingly complex problems with these.