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Curly hair is inherited autosomal dominant fashion: Attached ear lobes are autosomal recessive: A man and woman who are both heterozygous for both traits marry: Ans...

Question

Curly hair is inherited autosomal dominant fashion: Attached ear lobes are autosomal recessive: A man and woman who are both heterozygous for both traits marry: Answer a and b using: H/h for hair and Ele for ear lobes.Assume these traits exist on separate chromosomes and exhibit independent assortment: What is the probability this couple will have child with straight hair and unattached ear lobes?Assume these traits are linked on the same autosomal chromosome The dad'$ alleles are linked: H

Curly hair is inherited autosomal dominant fashion: Attached ear lobes are autosomal recessive: A man and woman who are both heterozygous for both traits marry: Answer a and b using: H/h for hair and Ele for ear lobes. Assume these traits exist on separate chromosomes and exhibit independent assortment: What is the probability this couple will have child with straight hair and unattached ear lobes? Assume these traits are linked on the same autosomal chromosome The dad'$ alleles are linked: H-e and h--E_ The mom's alleles are linked: H--E and h--e. What is the probability this couple will have child with straight hair and unattached ear lobes assuming no crossover event occurred?



Answers

Assume that long ear lobes in humans are an autosomal dominant trait that exhibits $30 \%$ penetrance. A person who is heterozygous for long ear lobes mates with a person who is homozygous for normal ear lobes. What is the probability that the ir first child will have long ear lobes?

So this question asks, um, about a trait that has 30% Penn Insurance, Um, and the probability that a person who is head rose, I guess, who mates with holes? I guess that the probability will have long year lows. So to have a long, long ear lobes, the traumas inherit the dominant Leo and also express it. The probability of inheriting the dominantly list 50% and the probability of expressing is 30%. And you have to do both in order to actually have the tree. So the combined probability of this if you put this into decimals, it be 0.5 times 0.3 much eagles 0.15 which is equal to 15%. So that is a probability of them having this treat of long your lobes.

This question asked. Suppose that in a mammalian species, the only over black hair be is dominant to the illegal for brown hair, lower case be and the olio for curly hair. Upper Casey is going to be dominant to the olio for straight hair. Lower Casey. When an organism of unknown geo type is cross against one with straight brown hair, the fino too big ratio is as follows by 5% curly black hair, 25% straight black hair, 25% curly brown hair and 25% straight brown hair. What is the Gino type of the unknown parent? So we're given an organism one parent, which is going to be, uh, straight brown hair. Well, we know that straight is going to be this lower Casey and Brown is going to be this lower case be. So that means that one parent parent one is going to be lowercase b lowercase b o k c l o k. C. Right, because we're talking about two different trades here. Now we're going to perform a die hybrid cross, but in this situation, we don't know who parent to is, right. Number two is going to be unknown. However, we know that it produces based on the mating pattern with, uh, this parent one we know that the results are going to be 25% curly black hair playing 5% straight back here, 25% curly brown hair and 25% straight around here. So, knowing this, we can perform a test cross with one a parent being on the left hand side here. All right, if we think about the way that we would write this out while we just take, uh, all of the different combinations from these Grammies and we know that the only, uh, gah means that could be produced by parent one would be the lower case being ill RKC. So if we are to test out all of the other possibilities, well, we can, for our different possibilities here for a parent to we don't know which one is going to be the correct one. But if we are to perform this cross, what we find is that as a result of this table right here, we produce 25% that is black and curly, 25% that is black and street 25% that is going to be brown and curly. And 25% that is going to be brown and straight. So what does this tell us? Well, this tells us that our second parent must be had a rose agus for both a wheels. So the parents gino type should be choice D right. On upper case, be a lower case, be in Upper Casey in a low K. C. Because these, uh, this kind of Gino type right here yields these potential combinations. And that is how we get the results which are stated in the problems. That is my choice. D the correct answer.

Implies the presence of a dominant B yields straight hair, whereas the presence of homeless I guess recess it for bees yields bitch hair. However, if the fly has a capital I or a dominant I'll Leo, that fly will be hairless regardless of what Gino type it has for hair shape. And so that also tells us that two little eyes we know that has no FINA type. So that means that a fly that has straight hair must have two little eyes and one big B. And so the question, for a part, says, What are the Gina types of FINA types of parents as one and F two from a breeding event from a straight here fly with a fly that was hairless but is no to have Vint Gino type, which the scientists would have to tell us. We could not infer that from the information provided it had to be told to us, it's a straight hair means that this fly is recessive for I because little eyes have no fino type and straight hair is big big. We have to assume that these flies were true breeding and hairless needs that that fly is homicide is dominant for hairless So big I, big guy and bent to Little Bee's and those who are parents. And so in the F one that crosses pretty easy. That fly for those flies are headers, I guess, for both traits and their hairless with the hidden strata Leo and a hidden bench the wheels. And so if we do an F one by F one Cross, we can expect that the offspring in the F two we'll have a 9 to 33 to one ratio. Because you have to jeans, I assume that they independently is sort. Otherwise, the question would have to tell us. And so we know that the feeding typical ratio in the F two is 9331 So that means nine flies will have a dominant olio for hairless and a dominant olio for straight and said they will be hairless. Three flies will have a dominant A Leo for hairless and ah, homeless, I guess process of state for bent that they will be hairless because of the presence of that ought. Assemble dominant Khalil. Three flies will have two little eyes and have a big B and something, and so that Fly will have straight here. And then the last individual will have been tear and be the double recessive. And so, uh, just used the information you have to fill in what? No and then work your way through this problem. But we can take that approach to be, he says. What are the parents Gina types If the offspring are four hairless, three straight and one bit. And so if we start out, let's write down everything we know and so hairless has to be big eyes, something, something, something. Because we don't know if they have the strata. Leo's works. The bins on wheels, straits and bends are easier because they have to have ah, homeless August recess it for I because they have hair and straight is gonna be big Be something and benches too little beast because we know that Vince is the double recesses. So let's start out writing the parents based on the information we have. And so we know that each parents must have one little I and a little be otherwise. This Gina type for the bent individual is not possible, and so we can easily right the parents genotype like that with something little eyes, something little. Being cross food is safe now. The second little tidbit that's over here that we can use to our advantage is the presence of a dominant eye in these hairless individuals and the presence of a dominant be in the straight hair individuals. And so that tells us that only one parent at this point we're not moving forward. One parent contains an IA Leo that's dominant and a B khalil that started it. And so what we could do is just stick those a wheels in the first parents Gina type, and we have that we're finished. The second piece of information that's here is if we look at the Gina typical ratio. It was a female typical ratio. We have a ratio of hairless, which is four t to haired, which is also for that's 1 to 1. The way to get a wonder one ratio is to breed a headers. I go with the homeless August recess of individual, and so because we could do a quick cross here and we can see big I little I two little eyes. They guide little I bigeye little like those two will be hairless. And then the two little eyes here would have hair. And so that's what we have. We have a wonder one ratio of hairless two straight that tells us that one parent is headers, I guess for I and the other parent is homeless, I just recesses for I using the same strategy, but a different characteristic. We can determine the be part of this second parent off the flies that have hair. We have three of them with straight hair and one of them with men's hair. So the only way to get it 3 to 1 ratio is to breathe to headers. I gets together, and so if we do a quick cross here, what we would see is that three of the individuals would have straight hair, as indicated by the big B. So 123 and only one individual will have been Well, that's what we have in our ratio in the this offspring batch. And so that means that this parent is think Big B and the second pier must also be, I think, the little B. And so my advice from problems like this take it for what it's worth it's right down as much information as you can and then work your way through each gene with the knowledge you have because you have so much college you have 93 321 at punitive pick ratio, where you could look for 1 to 1 or 3 to 1, and then you could tackle these seemingly complex problems with these.

Hello, everyone. Today I will be helping you with the 28 problem of the Chapter 12 problems. And and this question is asking basically to calculate the percentage that, um, the kid of a father with a widow's peak and a woman with a straight hairline having a kid. What's the probability of that one having a widow's peak? And ah, the widow's peak is a model, Really dominant trade is when on the wanna Leo controls the trait so it could be a or little a. And then you know that the father's mother had a straight hairline, but okay, so the thing is, is that the mother could have passed it down to the sun and since it has excess and then the sun showed the trade because it's ah mano Li lick. And then the sun had a fur dominant. And in this on, the mother of the child had a so it's really a 25% chance of it. Actually, actually, it's no sorry it's not 25% 25% say, but it's actually it's a 25% chance because he gave the child, whether it's a girl or boy could um, get either the What does beak, which is right here. So Widow's Peak or the street hairline? It's 50% because it's a model only, like, um, trait. So it's either or so that is B. So if you found this helpful and I hope you have a great day, thank you.


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