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The Ksp value for barium sulfate (BaSO4) is 1.1x 10^_10.Calculate the molar solubility of barium sulfate;BaSO4(s)< ---> Ba+2 (aq ) + S04 -2 (aq:)ulbvi 5.5 x 1...

Question

The Ksp value for barium sulfate (BaSO4) is 1.1x 10^_10.Calculate the molar solubility of barium sulfate;BaSO4(s)< ---> Ba+2 (aq ) + S04 -2 (aq:)ulbvi 5.5 x 10^_11 M11x 10^-5M1x 10^_10 M2.2x 10^_10

The Ksp value for barium sulfate (BaSO4) is 1.1x 10^_10.Calculate the molar solubility of barium sulfate; BaSO4(s)< ---> Ba+2 (aq ) + S04 -2 (aq:) ulbvi 5.5 x 10^_11 M 11x 10^-5M 1x 10^_10 M 2.2x 10^_10



Answers

Use the given molar solubilities in pure water to calculate Ksp for
each compound.
a. MX; molar solubility = 3.27 * 10-11 M
b. PbF2; molar solubility = 5.63 * 10-3 M
c. MgF2; molar solubility = 2.65 * 10-4 M

Now we'LL work on problem eighty eight from chapter seventeen. Look here for several compounds were given Mueller saw liability and were asked to calculate the K S P. So for every other equations are the chemicals we can draw the equation for the dissolution of Thie Ionic compound. So first we have very, um Romain. And that could dissolve to form barium two plus and crewmate C R o four to minus. Now if we draw our his table, we have no initial concentration change of s. And so now we're given Mueller Selya bility. So we have K s p is able to s squared from this here s times ass and this is equal to, um or we can plug in for s since that's what we're given in the problem. One point zero eight times ten to the menace. Five five. Let's make sure this looks like a five. Yeah, squared. And so if we take the square root of both side, we can get s is equal to one point one seven times ten to the minus ten so we can move on to part B where were given silver, so fight a G too s o three solid dissolving to form silver, two silver kid ions and the soul fight. And I wonder so if we draw our eyes table we have no initial concentration of the ions We're gonna add two s because of the coefficient of silver s of so fight as to s equilibrium for silver. And as for Sophie So when we have this the's terms here for the equilibrium concentration the K S P will be equal to four s cute and we can go ahead and plug in our Mueller Sally ability here, which is one point five five times ten to the minus five. And when we do this calculation, we did a value of one point four nine times ten to the minus fourteen. Now, for the third part, part C, we're given palladium fire scientist P. D. S C. And No. Two, which is a solid and can dissolve to give palladium. Two plus are curious and then too s c n minus minus. You do our ice table and we can draw our term for chaos p which, because we have s into a s when we multiply them together and square two s we had four as cute, which comes from here to be clear. And so when we plug in the value that were given for S which is two point two two times ten to the minus eight huge, we get a value of four point three eight times ten to the minus twenty three.

So now we work on problem eighty six from chapter seventeen. So here we're calculating the Mueller Sally ability based on the cast piece SAI Ability product constant. And for the first one were given a generic equation X So we can write the equation for the dissolution of this compound in water. It couldn't be him to plus or m plus or and three pluses. Long as thie ex has the same charge. So it doesn't matter based on this for the story geometry, it's a one to one ratio. So for both of them will be adding s and we have equilibrium. Concentrations of s so caspi is equal to these two concentrations multiplied by each other equilibrium concentrations which is equal to its given in the problem one point two seven times ten to the minus thirty six, which is equal to X squared. So when we take the square root of both sides, we get s is equal to one point one three times ten to the minus eighteen, which is our answer for a So if we move on to party now, were given an actual molecular formula for silver Crow made silver to see R O for solid and could potentially dissolve the form two silver plus ions and one chrome it. So we draw our eyes table Disregard the solid new initial concentrations we had to s because of this co efficient. We add us to S s So we need to draw our equation here. So K s P is equal to silver concentration squared because of the coefficient in chrome eight multiplied bankrupt me and this is equal to from table seventeen point to one point one two times ten to the minus twelve table seventeen point to which is equal to we have to s squared times s so this is equal to four s Cute. If we square inside the princess we get for a squared times s is equal to for us Cute. So to solve here we need to multiply. We need to divide both sides here by four and take the cube root. And when we do this to both sides gets six point five for times ten to the minus five. So for part three for party scene, we're given calcium hydroxide No which can dissolve to form calcium to bless close to hard drugs right in our hands When we draw the ice table we have a change of s for calcium and two es for hydroxide And we'LL have a cool librium Concentrations of s and to us So we drunk A s P is equal to a four point six eight times ten to the minus six from the table table seventeen point two And as I mentioned on the last page, we're due for as Cube because we have to s squared kinds of s And so we divide both sides by four to cancel And then we have to take the cue route as well of everything. And when we do that, we get asked is equal to one point zero five times ten the minus two Mueller which should be the concentration for all of our We should be the unit for all of our answers

To calculate the scalability of strontium sulfate in a solution that is .23 molar sodium sulfate. We first need to know the K. S. P. Value of strontium sulfate. We can look that up in the Appendix and it's 2.5 times 10 to the -7. So Kay sp is going to be equal to the strontium concentration, multiplied by the sulfate concentration. Sulfate concentration is coming from sodium sulfate. So it's provided at 23 moller. That then allows us to rearrange the equation to solve for a strong tea um concentration which will also be equal to the Mueller scalability. Because every time we get one mole of strontium in solution, one mole of strontium sulfate has dissolved. So one point oh nine times 10. The negative six moles of strontium sulfate will dissolve in a leader of solution, producing a 1.8 times 10. The negative six molars strontium concentration. We then take this concentration and moles of strontium sulfate per liter and convert it to grams by multiplying by the molar mass of strontium sulfate. So the soluble itty and grams per liter is 2.0 times 10. The negative four

So here we have a specific chemical reaction where we have Barium sulfate solid dissolving into barium two plus Aquarius and sulfite. And I, So based on this information, we were given information that the scalability of our salt 0.00 to five g, her one L of solution. And for scalability scalability, specific amounts of barium sulfate that dissolves. And we know that our K. Sp is equivalent to the concentration Bury him two plus times the concentration of sulfite which is equivalent to the solid ability square. However we need our uh solid ability in terms of concentration. Uh So we have to convert this into moles. So in one essentially one mole of barium sulfate, The Molar Mass is 233.38 g. So we can find that the scalability in this case Is equivalent to 1.05 times 10 to the -5 molars. And we can substitute this value into our K. Sp expression, which leads us to find that the K sp Is equivalent to 1.1 times 10 to the -10. And this is our final answer.


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