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Iredox reaction? lyes noc6) + 0,(g) cO, (g)reducing agent:oxidizing agent:redox reaction? yes nol2Ca(s) +02' (g) 2Ca0(s)reducing agent:oxidizing lagent:redox r...

Question

Iredox reaction? lyes noc6) + 0,(g) cO, (g)reducing agent:oxidizing agent:redox reaction? yes nol2Ca(s) +02' (g) 2Ca0(s)reducing agent:oxidizing lagent:redox reaction? yes Dlinoreducing agent:ANO; (ag) + H,o() 56 H,0" (aq) + NO; (ag)oxidizing lagent;

Iredox reaction? lyes no c6) + 0,(g) cO, (g) reducing agent: oxidizing agent: redox reaction? yes nol 2Ca(s) +02' (g) 2Ca0(s) reducing agent: oxidizing lagent: redox reaction? yes Dlino reducing agent: ANO; (ag) + H,o() 56 H,0" (aq) + NO; (ag) oxidizing lagent;



Answers

For each redox reaction, identify the substance being oxidized, the substance being reduced, the oxidizing agent, and the reducing agent. (a) $\mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \longrightarrow 2 \mathrm{HI}(g)$ (b) $\operatorname{CO}(g)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g)$ (c) $2 \mathrm{Al}(s)+6 \mathrm{H}^{+}(a q) \longrightarrow 2 \mathrm{Al}^{3+}(a q)+3 \mathrm{H}_{2}(g)$

Sir. For part, a nitrogen is oxidized as it gained oxygen and or to gain electrons so it is reduced. So into east nitrogen. Introducing agent and or two is oxidizing Agent answer for part B. Carbon monoxide is oxidized. Is it gained Oxygen and or two gained electrons. So you taste reduced. So carbon monoxide these reducing agent and or to east oxidizing agent he answer for Parsi, SBC L three is oxidized as it gained oxygen and C l two gained electrons. Yeah, so it tastes reduced. So s B C l three introducing agent and C L two is oxidizing agent answer for party petition Miss Oxidize Is it gained oxygen and let plus to gain electrons so it is reduced. So protection is reducing agent and PV plus two. He's oxidizing, isn't

For this question, we have four chemical reactions for which we need to identify what is oxidized, What is reduced, What is the oxidizing agent and what is the reducing agent? The first chemical reaction is potassium reacting with water producing potassium hydroxide and hydrogen gas. If we assign oxidation states, elements by themselves have an oxidation state of zero, oxygen is always minus two, hydrogen is always plus one unless they're by themselves. So we go over to potassium, its oxidation state as its charge plus one. Again, oxygen is minus two, and hydrogen is plus one, But hydrogen here by itself is zero. So we see that water is being reduced. It has an element hydrogen that is going from a plus one oxidation state to zero. That reduction results in water being reduced, reduction and oxidation state means reduction and it then serves as the oxidizing agent. potassium, however, is going from a zero oxidation state. It is increasing an increase in oxidation state means oxidation. So potassium is oxidized and it serves as the reducing agent. It's always the opposite. Whatever is oxidized is the reducing agent and whatever is reduced as the oxidizing agent. The next one we have methane CH four reacting with oxygen producing carbon dioxide and water. When we assign the oxidation states, hydrogen is plus one, there are four of them, so that's plus four. So carbon needs to be minus four. Oxygen by itself has an oxidation state of zero, but in carbon dioxide it's minus two, there are two of them, causing carbon to have a plus four oxidation state And then oxygen and water has an oxidation state of -2 and hydrogen plus one. So we see in this case that methane has the element carbon that shows an increase in oxidation state. So methane is being oxidized and serving as the reducing agent, oxygen is going from a zero oxidation state to a minus two oxidation state in two separate compounds. So because oxygen has a decrease in oxidation state, oxygen then is reduced and it serves as the oxidizing agent. The next one is permanganate, reacting with iron two plus producing hydrogen ions are with hydrogen ion producing Mn two plus iron three plus and water. So if we assign oxidation states, oxygen is -2, there are four of them. So that's -8, So with -8, we need a plus seven, so that plus seven and minus eight gives us the charge of minus one. Oxidation states must always some up to the charge of the species Here, iron two plus its oxidation state is its charge, Hydrogen, its oxidation state is its charge. The MN two plus its oxidation state is its charge, and the F E three plus the oxidation state is its charge. And then in hydrogen, hydrogen is always plus one unless it's by itself and oxygen is typically -2 Unless it's by itself where it's zero. So here we see manganese and permanganate going from plus seven two plus two. That's a decrease in oxidation state. Therefore that's reduction. So we would say M n 04 minus is being reduced and it is serving as the oxidizing agent, the M N 04 minus as the oxidizing agent. And then we see Effie two plus going to F E three plus. That's an increase in oxidation state. An increase in oxidation state means oxidation. So F. E. Is being oxidized and it's serving as the reducing agent. And for the last one we have magnesium reacting with Copper two sulphate producing copper and magnesium sulfate. Magnesium by itself has an oxidation state of zero. Copper has an oxidation state of plus two, which is its charge, And then sulfate the whole charges -2. So the oxidation states need to send a -2 oxygen is minus two, but there are four of them, so that's minus eight. So we need a plus six to have everything some up to -2. Copper. All by itself has an oxidation state of zero. Magnesium has a charge of two plus. So it's oxidation state is two plus in magnesium sulfate and then the sulfate, oxygen and sulfur end up having the same oxidation states as they did over here. So we can focus on Copper. Copper is going from an oxidation state of plus 2-0. Therefore that's a reduction. So copper sulfate is being reduced and it's serving as the oxidizing agent and then magnesium goes from an oxidation state of 02 plus two. So it is being oxidized and serving as the reducing agent.

Hello, everyone. Thanks for joining as we I d substances oxidized and substances reduced. Please remember that the substance oxidized is the reducing agent and the substance substance reduced is the oxidizing agent. Let's begin. Okay, We're going to start with this problem and it's pretty easy to see that 10 and chromium are substances in question. Let's start with chromium in this substance on the react inside Crow me chromium. If oxygen contributes a negative 14 and I have a negative to overall charge chromium and this should be a two. I copied this down wrong. I feel terrible for that, but at least I noticed it. Now there's a to chromium is going to have to be a positive six to give me a plus 12. So chromium is a plus six on this honor react inside, and it is a plus six on the product side as her plus three on the product side. So chromium is going from a positive six charge to a positive three charge. In order to do that, chromium had to gain electrons. Therefore it's reduced and it is the oxidizing agent. Okay, Next, let's take a look at 10. 10 is a two plus on this side on the reactant side, and it's a four plus on deposit on the product side. So 10 is going from a positive too, to a positive four, which means it had to lose electrons. Therefore, it underwent oxidation. It's oxidized, which means it's the reducing agent. Okay, one more. This one is also pretty easy. We take a look at this. Let me go toe orange and we can see Oh, I bet you anything something is going to be happening to my iron. And it is We can easily see that iron on the react inside. Is it positive church to charge? So iron is going from a plus two to a plus three. In order to do that, it had to lose an electron. So it is oxidized and it's the reducing agent. And next, um, as you get more practice that with this, you'll get better and better at it. But nitrogen is a likely candidate for undergoing something on the react. Inside. This nitrogen has a plus five. This nitrogen on the product side has a plus two. So nitrogen is going from a positive five to a positive too which means it had to gain electrons. Therefore it underwent reduction. And it is the oxidizing agent. Thanks for listening.

This is the solution of problem number 40. So we know that the oxidation occurs when a substance loses electron and increase its oxidation number, whereas reduction occurs when a substance gains electron and decreases oxidation number. So this is the given decoration. So based on the reaction, I sent a positive uses electron and increases is oxidation so reacting, oxidized and reducing engenders yes, and to positive and react introduced. An oxidizing agent is their toe or seven to negative. So this is the part B, and they have given this equation. So again we know that oxidation occurs and the substance loses electron and in prison oxidation number. Where is with production occurs when the substance gains electron and the crisis is observation. So again, this based on this equation, wrecked and oxidized and reduce the dentist f es and react introduced an oxidizing agent is and a three negative


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