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A sample of Epsom Salt of mass 0.6724 g was dissolved uniformly in distilled water in a 250m] volumetric flask Portion of the magnesium ion (Mwt 24.3g/mol) solution...

Question

A sample of Epsom Salt of mass 0.6724 g was dissolved uniformly in distilled water in a 250m] volumetric flask Portion of the magnesium ion (Mwt 24.3g/mol) solution of volume 10 ml were titrated using a 0.01 M solution of EDTA The mean corrected titration volume was 12.50 ml Calculate the percentage by mass (wlw %) ofthemagnesium in the Epsom Salt sampleSelect one0 a 10,5 %0,.25 %11.3 *54,2 %

A sample of Epsom Salt of mass 0.6724 g was dissolved uniformly in distilled water in a 250m] volumetric flask Portion of the magnesium ion (Mwt 24.3g/mol) solution of volume 10 ml were titrated using a 0.01 M solution of EDTA The mean corrected titration volume was 12.50 ml Calculate the percentage by mass (wlw %) ofthemagnesium in the Epsom Salt sample Select one 0 a 10,5 % 0,.25 % 11.3 * 54,2 %



Answers

Epsom salts are hydrated crystals of magnesium sulfate, $\mathrm{MgSO}_{4} \cdot x \mathrm{H}_{2} \mathrm{O} .$ When $6.499 \mathrm{~g}$ of Epsom salts are dehydrated by heating, 3.173 g remain. What is the mass percent of water in the hydrated sample? What is $x$ ?

From the giving caution. We have general formula off Epsom soul that is M G s 04 multiplied by X amount off edge tool mass off Epson sold along with water Hydration is 4.93 grams mass after dehydration is 2.41 round. So the amount off water present will be two point to five gram, hence the number off moles off water can be calculated. Witches 0.14 months by the number off. Mold off salt after dehydration turns out to be 0.20 Moles the number off morals. We can write this Udo formula from the above element which is represented as shown. We divide the simplest value toe obtain the ball in teacher value which gives MGs 041 to really show off water seven. Hence the empirical formula is MGs 04 Indo seven edge dual

To answer this question, we need to calculate the moles of magnesium sulfate and the moles of water. We can calculate the moles of magnesium sulfate by taking the grams of barium sulfate and converting them two moles of barium sulfate. Every mole of barium sulfate was created from one mole of magnesium sulfate, Barium sulfate being the precipitate. Then when we have moles magnesium sulfate, we can multiply by the molar mass to get the mass of magnesium sulfate. But right here, if we were to stop We would get moles magnesium sulfate as 5, 3 times 10 to the -3 moles. To calculate the moles of water, we need to take the mass of the hydrate and subtract off the mass. That is just magnesium sulfate and the rest will be the mass water. We then divide that by the molar mass of water. To get the moles of water 3.52 times 10 to the negative too. Now we want to figure out the moles of water for every mole of magnesium sulfate. So let's just divide these two. And in doing so we get seven, that means that there are seven moles of H 20. For everyone more magnesium sulfate or the formula is mgs oh 4.7 H two OO

Good day. In this question we will be solving for the waters of hydration. X. So in order to do this, we need to first told the mass of watery so must of what three is equal to the mass of hydrated compound which is the M G. S. O. For X. H 20. My nurse the mass of and high interest compounds In the question we are given that the mass of hydrated compound is 4.93 g. My nurse, the anhydrous is What to .41 g. Therefore Months of War III is equal to 2.52. Perhaps. No solving for the most of water and most of the anhydrous compound we have more water is equal to mass over mahler mass, which is smaller. Mass is the sum of all the atomic masses of the elements given in the compound. So do find 52g divided by 18.02 g per mole Is equal 2.13 98. And malls MGS. sequel to Mas grandmother. Must We have to 0.41 g divided by 1 20 .37 Ground Super Bowl, which will give us 102002 Most. Now X. Is there asia between moral of watery over more of the anhydrous compounds? Therefore X equals mole H 20. Where more mg S. 04 equal to .1398 moles invited by .02002. Well and then are solving these X is equal to seven. This will give us, yeah, I traded compound of MGS 047 H 20. Thank you.

We're starting with magnesium, so feats hydrate and we don't know how many hydrates were told that the entire hydrate has a massive 4.93 grabs. After we removed, the water will be left with just magnesium, so feet, which were told, has a mass of 2.41 grams after dehydration. Therefore by subtraction here will find that the mouth of the each to O present is 2.52 grams. So let's solve for the moles of H 20 So we have 2.52 grams of H 20 and 18.0 grams per mole would yields 0.14 moles of H 20 And we could also solve for, uh, the moles of magnesium. So feats, which has a molar mass of 120.4 grams per mole and will gets 0.200 moles and we'll divide by the least and we'll get one and seven. Therefore there seven h 20 zoos and the formula B M. G s 4.7 each, 20


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