Which of the following organic compounds is the strongest_ acid?C6H12 pKa 52CH3CH3 pKa 50CH3CHZOH pKa 18CH3COZHpKa = 5CF3COZHpKa = 0...

At $\mathrm{pH} 4.5$, which of the following acids would be most dissociated? (a) Hexanoic acid $(\mathrm{pKa}=4.88)$ (b) $\mathrm{p}$ -Nitrobenzoic acid $(\mathrm{pKa}=3.4 \mathrm{I})$ (c) Octanoic acid $(\mathrm{pKa}=4.89)$ (d) Acetic acid (ethanoic acid) $(\mathrm{pKa}=4.74)$

ACSI oh, add at C o AD has the, as the low wished as the low waist PK value. The couch be cowed. It is the strongest acid. It is the it is the the strongest as soon as it is the strongest acid. This is the reason behind its lowest pick A value. Therefore, according to the option option B, option B h, correct answer for this problem.

Question is among the following assets which has the lowest PK value. So as the value of PK, decreased gender, athletic strength is increased. Okay, so in the athletic strength of carbolic acid, as the electron releasing group increased gender, acidic strength will be decrease. So to identify the value of peak, which is lower west. That molecules should have minimum number of alcohol group. Because then as medication will be increased so we can observe that in the B molecule that is at sea Devil was farming acid, farming acid? Do not have any electron releasing group. So this molecule will be acidic molecule and acidic molecules highly acidic molecule have lower west menu of PK. Okay, thank you.

Among the given compounds among the given components, this compound, which I am doing here, just look at it carefully. Heritage the well born or heritage they were born to expected to be to be the strongest car. When I said, the strongest got a button as it two according to the given options here, option, age, correct answer option, Age Barrick Pensar for this problem.

This question asks which of these compounds is the strongest F? It s a one way that we can measure Acidity is by looking at the stability of the conjugated base eso We're gonna drop the combat base for each one of these structures and then look at the stability of each one. So if we had a conjugal based for this first structure, um, be that over? Okay, so for this first one used are still here, and then let's put the lone pair right here so they can interact with the pie system. Um, so here, if I were to have this company based, I could push this in here and push this up onto here, which would give me a president's form that would look like this and others alone. Pierre here. This is my negative. Now this is up here. This is appear and so that this is the residence for so we can get it. We can keep moving on around the ring if we want to, but that's not really gonna change anything, but I want to look at here is the ring. So this ring has four electrons in it. Um, which means but it is anti aromatic. Um, it's anti aromatic because follows all the aromatics city rules. Except for the number of electrons, it has the fore end number of electrons instead of four n plus two, which makes it anti aromatic, which is in that stable. If we go to the second compound here, if we had the conjugal base of this one would have along here on one of these carbons down here this we can move like this. Push this into the ring like that, and that would give us a residence form that looks like this. So this is my negative. Um, and I have this over here. So now this one has six electrons in the ring, which is a foreign plus two number, and this is aromatic. Switzerland has a resonance form that is aromatic, making it very stable. If we look at the third one, let's say that I pulled the hydrogen off. Well, it could come off here or here if it came off of here, and we would have four electrons and the ring again like we did in the first one that would be anti aromatic if it came off of here. Let's draw that and find out what happens. So if I pulled it off of here, this is my negative. That I could move this Teoh here and push this to here. Um, and then that would give me a residence form that I would look like this. So this is still here. And now I have, um, the lone pair here and my double bond here. So this also has four electrons in its rain. No matter where you take it off their here or here. Which means that this is also, um uh, actually, this one is non aromatic, not anti aromatic, because it has an SP three carbon in the ring right here. So this one is non aromatic in its residents contributors. So, like I said before, the one with the most stable conjugated base is going to be the strongest asset because it's easiest to form that face because it's the most stable. So that means that this one is going to be the strongest asset because he form this aromatic ring in our contact base.